Respuesta :
Answer:
Step-by-step explanation:
We have two functions:
[tex]D(x) = 5000e^{0.02x} \text{commodity}[/tex]
[tex]E(x) = xD(x) \text{expenditure}[/tex]
firstly, we can express D(x) in the above equation.
[tex]E(x) = 5000xe^{0.02x}[/tex]
Thinking of the questions mathematically,
part a) is only asking what is the rate of change of the expenditure(E) with respect to x(price) when x is 110 dollars? that is,
[tex]\left\dfrac{dE}{dx}\right|_{x=110}}[/tex] evaluated at x = 110.
[tex]\dfrac{dE}{dx} = \dfrac{d}{dx}\left(5000xe^{-0.02x}\right)[/tex]
using the product rule for differentiation.
[tex]\dfrac{dE}{dx} = 5000(-0.02xe^{-0.02x} + e^{-0.02x})[/tex]
for simplification we can take e^0.02x common
[tex]\dfrac{dE}{dx} = 5000e^{-0.02x}(-0.02x + 1)[/tex]
now put x= 110, and we'll get the rate of change of the expenditure at x = 110. (answer for part a):
[tex]\dfrac{dE}{dx} = 5000e^{-0.02x}(-0.02x + 1)[/tex]
[tex]\left\dfrac{dE}{dx}\right|_{x=110}} = 5000e^{-0.02(110)}(-0.02(110) + 1)[/tex]
[tex]\left\dfrac{dE}{dx}\right|_{x=110}} = 5000e^{-0.02(110)}(-0.02(110) + 1)[/tex]
[tex]\left\dfrac{dE}{dx}\right|_{x=110}} = -664.82\,\text{dollars}[/tex]
part(b) at what value of x does E'(x) = 0? i.e, at what price(x) does the expenditure E changes from increasing to decreasing?
[tex]\dfrac{dE}{dx} = 0 [/tex]
[tex]5000e^{-0.02x}(-0.02x + 1) = 0[/tex]
we can split the equation and solve them separately.
[tex]5000e^{-0.02x}=0\,\,,\,\,(-0.02x + 1) = 0[/tex]
[tex]-0.02x=\ln{(0)}\,\,,\,\,(-0.02x + 1) = 0[/tex]
[tex]\text{ln(0) cannot be solved}\,\,,\,\,x = 50[/tex]
at x =50 dollars, the price changes from increasing to decreasing.
part(c) is only asking: from what value of x is the price increasing.
Well, judging from the answer of E'(x) = 0, the only value from where the price is changing from increasing to decreasing is x =50. so, the price has been increasing from x < 50. BUT since price cannot be negative (depending on the context), we can't say [tex]x = -\infty [/tex], instead our answer should be: that the rate of consumer expenditure (dE/dx) begin increasing from x = 0.
The consumer expenditure rate at 110 dollars is -664.82. The consumer rate stop at x = 50. And the rate of cosumer expenditure (dE/dx) begin increasing from x = 0.
What is an exponent?
Exponential notation is the form of mathematical shorthand which allows us to write complicated expressions more succinctly. An exponent is a number or letter is called the base. It indicates that the base is to raise to a certain power. X is the base and n is the power.
Given
The demand for a certain commodity is [tex] \rm D(x) = 5000e^{-0.02x} [/tex] units per month when the market price is x dollars per unit.
(a) The consumer expenditure E(x) = xD(x) changing with respect to price x when the price is equal to $110 dollars.
[tex] \rm E(x) = xD(x) \\\\ E(x) = 5000xe^{-0.02} [/tex]
Then
[tex] \rm \dfrac{dE(x)}{dx}|_{x=110}[/tex] evaluated at x = 110.
[tex] \rm \dfrac{dE}{dx} = \dfrac{d}{dx} (5000xe^{-0.02x})[/tex]
Using product rules for differentiation.
[tex] \rm \dfrac{dE}{dx} = 5000(-0.02xe^{-0.02x} + e^{-0.02x ) \\\\\dfrac{dE}{dx} = 5000e^{-0.02x}(-0.02x + 1) [/tex]
At x = 110, then
[tex] \rm \dfrac{dE(x)}{dx}|_{x=110} = 5000e^{-0.02*110} (-0.02*110 + 1) \\\\\dfrac{dE(x)}{dx}|_{x=110} = -664.82 [/tex]
(b) The consumer expenditure stop increasing and begin to decrease.
At E'(x) = 0 that is
[tex] \rm \dfrac{dE}{dx} = 0[/tex]
Then
[tex] \rm 5000e^{-0.02*110} (-0.02*110 + 1) = 0 [/tex]
On simplifying, we have
[tex] \rm x = 50 [/tex]
At x = 50 dollars, the price changes from increasing or decreasing.
(c) The rate of consumer expenditure begins to increase.
Well, judging from the answer of E'(x) = 0, the only value from where the price is changing from increasing to decreasing is x = 50. So, the price has been increasing from x < 50. But, since the price cannot be negative, we cannot say [tex] \rm x = -\infty [/tex], instead our solution should be that
The rate of cosumer expenditure (dE/dx) begin increasing from x = 0.
More about the exponent link is given below.
https://brainly.com/question/5497425