Answer:
a) moves down
b) moves down
c) level remains same
Explanation:
Given that the anchor is initially on the floating boat.
a)
In this condition initially the the volume of water [tex](V_w_i)[/tex] displaced is to balance its weight.
Now,
[tex]W_a=W_w[/tex]
[tex]V_a.\rho_a.g=V_w_i.\rho_w.g[/tex]
[tex]\frac{\rho_a}{\rho_w} =\frac{V_w_i}{V_a}[/tex]
We've, the density of steel [tex]= 7850\ kg.^{-3}[/tex] and the density of water [tex]= 1000\ kg.^{-3}[/tex]
[tex]\therefore V_w_i=7.85\times V_a[/tex]
When the anchor is dropped into water:
The volume of water displaced be [tex](V_w_f)[/tex] which will be equal to the volume of anchor since it is immersed into it.
[tex]V_a=V_w_f[/tex]
[tex]\therefore V_w_i>V_w_f[/tex] ...................(1)
So the level of water falls when the anchor is dropped into water.
b)
Now, when the anchor is thrown on the ground the water has now less weight to balance so the water level falls down.
c)
When the cork on the from the boat is dropped into the water and it still floats then it must displace same amount of water, hence there should be no change in the water level.