A milk truck carries milk with density 64.6 lb/ft3 in a horizontal cylindrical tank with diameter 12 ft.

(a) Find the force exerted by the milk on one end of the tank when the tank is full. (Round your answer to the nearest integer.) lb
(b) What if the tank is half full? (Round your answer to one decimal place.)

Respuesta :

Answer:

(a) 1408366[tex]\frac{lb*feet}{sec^{2} }[/tex]

(b) 448524 [tex]\frac{lb*feet}{sec^{2} }[/tex]

Step-by-step explanation:

Pressure on a vertical surface by a static non-viscous fluid is =Pressure at center of mass of the surface *Area of surface covered by fluid.

A) acceleration due to gravity =9.8*3.38

   Radius =6

   So pressure at center of circular plate =density*g*R

      Total force =density*g*R*Area = 1408366 [tex]\frac{lb*feet}{sec^{2} }[/tex]

B) Here center of mass of semicircle sector is at [tex]\frac{2*R}{\pi }[/tex] from center.

 So pressure at center of mass of semicircle =[tex]\frac{2*R}{\pi }[/tex]*density*9.8*3.38

 Net force =[tex]\frac{2*R}{\pi }[/tex]*density*9.8*3.38*Area of semicircle =448524 [tex]\frac{lb*feet}{sec^{2} }[/tex]

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