Answer:
initial value=2
Step-by-step explanation:
equation of line,
y-[tex]y_1[/tex]=[tex]\frac{y_2-y_1}{x_2-x_1}[/tex][tex](x-x_1)[/tex]..............(1)
put co ordinate (0,3) and (2,7) in the equation (1)
y-3=[tex]\frac{7-3}{2-0}[/tex](x-0)
y-3=2x
y=2x+3
rate of change of linear equation=[tex]\frac{\partial (2x+3)}{\partial x}[/tex]
[tex]\frac{\partial y}{\partial x}[/tex]=2
hence, initial value=2 answer