Answer:
The equation of line is y = 3 x +18
Step-by-step explanation:
Given as :
The points are
([tex]x_1[/tex], [tex]y_1[/tex]) = (- 9, -9)
([tex]x_2[/tex], [tex]y_2[/tex]) = (- 6 , 0)
Let The slope = m
Now, The slope is calculated in points form
So, Slope = [tex]\dfrac{y_2-y_1}{x_2-x_1}[/tex]
I.e m = [tex]\dfrac{y_2-y_1}{x_2-x_1}[/tex]
or, m = [tex]\dfrac{0 - (-9)}{- 6 - (-9)}[/tex]
or, m = [tex]\dfrac{9 }{3}[/tex]
I.e m = 3
So, The slope of points = m = 3
Now, the equation of line in slope - point form can be written as
y - [tex]y_1[/tex] = m ( x - [tex]x_1[/tex] )
where m is the slope of line
i.e y - (-9) = ( 3 ) × ( x - (-9) )
or, y + 9 = 3 × (x + 9)
∴ y + 9 = 3 x + 27
Or, y = 3 x + 27 - 9
O,r y = 3 x + 18
So, The equation of line is y = 3 x + 18
Hence, The equation of line is y = 3 x +18 . Answer