Daily high temperatures in St. Louis for the last week were as follows: 93, 94, 93, 95, 96, 88, and 90 (yesterday).

a) Forecast the high temperature today, using a 3-day moving average.

b) Forecast the high temperature today, using a 2-day moving average.

c) Calculate the mean absolute deviation based on a 2-day moving average, covering all days in which you can have a forecast and an actual temperature.

You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.

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anthougo anthougo · Answer 2 · 2022-02-25T13:38:43+01:00

a) The forecast of the high temperature today, using a 3-day moving average is 91.3 (96 + 88 + 90)/3.

b) The forecast of the high-temperature today, using a 2-day moving average is 89 (88 + 90)/2.

c) The mean absolute deviation based on a 2-day moving average is computed as follows:

Daily High Temperatures in St Louis

Day Temperature 2-day Moving Average Absolute Deviation

1 93

2 94 93.5 (93 + 94)/2 1.1 (94 - 92.9)

3 93 93.5 (94 + 93)/2 0.1 (93 - 92.9)

4 95 94.0 (95 + 93)/2 2.1 (95 - 92.9)

5 96 95.5 (96 + 95)/2 3.1 (96 - 92.9)

6 88 92.0 (88 + 96)/2 -4.9 (88 - 92.9)

Yesterday 90 89.0 (90 + 88)/2 -2.9 (90 - 92.9)

Mean of dataset = 92.9 (557.5/6)

Mean of Absolute deviation = -1.4

What are moving averages?

A moving average is a statistical analysis tool used to capture the average change in a dataset over the stated time, e.g. two-day, three-day, etc. It helps in smoothing trends.

Data and Calculations:

Daily High Temperatures in St Louis

Day Temperature

1 93

2 94

3 93

4 95

5 96

6 88

Yesterday 90

Thus, based on a 2-day moving average, the mean absolute deviation is -1.4.

Learn more about moving averages https://brainly.com/question/15188858