Question

Determine the voltage across a 2000 pF capacitor that is storing 20 microcouloms (20 µC) of charge.

Answer 1

Answer:

V=  10,000 V

Explanation:

Capacitance= C= 2000 pF

Charge = q = 20 μC

Relationship between voltage, charge and capacitance of a capacitor is:

Q= CV

⇒ V = Q/C

⇒ V= 20* $10^{-6}$/$2000*10^{-12 }$

⇒ V=  10,000 V