I need heeeeeeeeeeelp
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Answer:
k=5
Step-by-step explanation:
The question states that <ACB=<DCE
And <ACE=(4/5)k-(1/10)k
<DCE=(1/2)k+1
So the equation is (4/5)k-(1/10)k=(1/2)k+1
Over here the LCM is 10 so you multiply through by 10 to get
8k-k=5k+10
7k=5k+10
7k-5k=10
2k=10
2k/2=10/2
k=5