Question

Please help!

N2 + 3H2 —> 2NH3
Suppose you have 2.0 L of nitrogen. How many liters of hydrogen do you need for a
complete reaction? (One mole of any gas occupies 22.4 L under certain conditions of
temperature and pressure. Assume those conditions for this question.)

Answer 1

Answer:

$\large \boxed{\text{6 L}}$

Explanation:

We can use Gay-Lussac's Law of Combining Volumes to solve this problem.

Gases at the same temperature and pressure react in the same ratios as their coefficients in the balanced equation.

1. Write the chemical equation.

Ratio:  1 L     3 L

           N₂ + 3H₂ ⟶ 2NH₃  

V/L:      2

2. Calculate the volume of H₂.

According to Gay-Lussac, 3 L of H₂ react with 1 L of N₂.

Then, the conversion factor is (3 L H₂/1 L N₂).

$\text{Volume of H}_{2} = \text{2 L N}_{2} \times \dfrac{ \text{3 L H}_{2} }{\text{1 L N}_{2}}= \textbf{6 L H}_{2}\\\text{You need \large \boxed{\textbf{6 L}} of hydrogen,}$