12. The equation for line G is given by
5y = -2x - 20. Suppose line G is parallel to line R, and line E is perpendicular to line G. Point (-10,8) lies on both line R and line E.
Part A: Write an equation in slope-
intercept form for line R.
Part B: Write an equation in slope-
intercept form for line E.

Respuesta :

Answer:

Step-by-step explanation:

line G :

5y = -2x - 20...put in slope intercept form (y = mx + b)

y = -2/5x - 4....the slope(m) = -2/5

Part A.) slope intercept form for line R...since R is parallel to G, it will have the same slope....so slope(m) = -2/5

(-10,8)...x = -10 and y = 8

slope(m) = -2/5

y = mx + b

8 = -2/5(-10) + b

8 = 4 + b

8 - 4 = b

4 = b

so ur equation is : y = -2/5x + 4 <=== part A answer

since line E is perpendicular to line G, it will have a negative reciprocal slope...all that means is flip the slope and change the sign....so the slope of line E is : (flip -2/5.....-5/2.....change the sign......5/2)

(-10,8)...x = -10 and y = 8

slope(m) = 5/2

y = mx + b

8 = 5/2(-10) + b

8 = -25 + b

8 + 25 = b

33 = b

so ur equation is : y = 5/2x + 33 <== part B answer

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