The four consecutive even integers are 20, 22, 24, 26
Solution:
Let the four consecutive even integers are a , a + 2, a + 4, a + 6
Let "a" be the smallest integer and "a + 6" be the largest integer
To find: the four consecutive even integers
Given that the greatest of four consecutive even integers is 14 less than twice the smallest integer
largest integer = twice the smallest integer - 14
a + 6 = 2(a) - 14
a + 6 = 2a - 14
a - 2a = -14 - 6
-a = -20
a = 20
Thus the four consecutive even integers are:
a = 20
a + 2 = 20 + 2 = 22
a + 4 = 20 + 4 = 24
a + 6 = 20 + 6 = 26
Thus the four consecutive even integers are 20, 22, 24, 26
