36 of 50 Constants A 89.0-kg refrigerator sits on the floor. The coefficient of static friction between the refrigerator and the floor is 0.60. What is the minimum force that one needs to exert on the refrigerator to start the refrigerator sliding?

This is a type of contact force that opposes motion between two surfaces in contact. It is measured in newton. Mathematically, frictional force can be expressed as,

Note: The minimum force needed to make the refrigerator to slid = The force required to overcome friction = Frictional force

F = μR............................. equation 1

⇒ Where :

F = frictional force,
μ = coefficient of static friction,
R = Normal reaction.

⇒ Note: On a level surface,

Normal reaction = Weight

⇒ Since the floor is a level surface,

R = W.............................. equation 2

⇒ Where

W = weight of the refrigerator.

⇒ But,

W = mg......................... equation 3

⇒ where:

m = mass of the refrigerator,

g = acceleration due to gravity

⇒ Given:

m = 89 kg,
g = 9.8 m/s²

⇒ Substituting these values into equation 3,

R = W = 89 × 9.8 = 872.2 N

R = 872.2 N.

⇒ Also given:

μ = 0.60

⇒ Substituting into equation 1

F = 872.2 × 0.6

F = 523.32 N

Hence, The minimum force needed to make the refrigerator slide is 523.32 N.

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