Answer:
Step-by-step explanation:
The GCF is the common "thing" in each one of the terms in our polynomial. Since 3 doesn't divide evenly out of 10, 3 is not a GCF. But b-squared is common in both. So for part A. the GCF is b-squared.
part B. Factor out the GCF:
[tex]b^2(3b+10)=0[/tex]
For part C. What are the solutions? The solutions are found in the Zero Product Property which states that if the factors of a polynomial, when multiplied together, equal 0, then either one of the factors or both of the factors have to equal 0 because 0 times anything equals 0. That means that
[tex]b^2=0[/tex] and/or 3b + 10 = 0
Solving the first equation:
[tex]b^2=0[/tex] and b = 0.
Solving the second equation:
3b + 10 = 0 and
3b = -10 so
[tex]b=-\frac{10}{3}[/tex]
