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The width of a rectangle is 3 inches less than the length. The area is 50 square inches. Find the length and width. Round to the nearest tenth if necessary

Respuesta :

Answer:the length is 8.7 inches. The width is 5.7 inches

Step-by-step explanation:

Let L represent the length of the rectangle.

Let W represent the width of the rectangle.

The width of a rectangle is 3 inches less than the length. This means that

L = W + 3

The area of a rectangle is expressed as L×W

The area is 50 square inches. This means that

LW = 50 - - - - - - - - - - 1

Substituting L = W + 3 into equation 1, it becomes

(W + 3)W = 50

W^2 + 3W - 50 = 0

We would apply the general formula for quadratic equations,

x = [ - b ± √(b^2 - 4ac)]/2a

a = 1

b = 3

c = - 50

Therefore,

w = [- 3 ± √(3^2 - 4×1×-50)]/2×1

w = [- 3 ± √(9 + 200)]/2

w = (- 3 ± √209)/2

w = (-3+14.4568)/2 or (-3-14.4568)/2

w = 5.7 or w = -8.7

Since the width cannot be negative, the width would be 5.7 inches.

Substituting w = 5.7 into L = W + 3,

L = 5.7 + 3 = 8.7 inches

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