You are in an airplane going down a runway currently going 24 m/s and accelerating at 8m/s for 800 meters until take off. How long does it take the plane to go those 800 meters?

Respuesta :

Answer:

Time taken to cover the distance 11.45 s.

Explanation:

The given parameters:

Initial Velocity(u)=24 m/s

Acceleration (a)=8 [tex]m/s^{2}[/tex]

Distance or Displacement(s)=800 m

Displacement or Distance is equal in the above because it travels in a straight line.

We have to apply Second Equation of Motion,

s=ut+[tex]\frac{1}{2} at^{2}[/tex]

800=24t + 4[tex]t^{2}[/tex]

200=6t + [tex]t^{2}[/tex]

[tex]t^{2}[/tex] + 6t - 200=0

Solving, the quadratic equation to find out the roots, we get that the possible values of t will be 11.45 s and a negative value.

The negative value will be neglected as time cannot be negative.

Hence, the time taken is 11.45 s.

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