Answer:
The area of Triangle B is twice the area of Triangle A .
Step-by-step explanation:
Given as :
Triangle A and Triangle B have same base
The height of Triangle A twice Triangle B
For Triangle A
The base of Triangle A = [tex]b_1[/tex] = b
The height of Triangle A = [tex]h_1[/tex] = h
Let The area of Triangle A = [tex]A_1[/tex]
∵ The Area of Triangle = [tex]\dfrac{1}{2}[/tex] × base × height
So, [tex]A_1[/tex] = [tex]\dfrac{1}{2}[/tex] × b × h ......1
For Triangle B
The base of Triangle B = [tex]b_2[/tex] = b
The height of Triangle B = [tex]h_2[/tex] = twice the height of Triangle A
I.e [tex]h_2[/tex] = 2 h
Let The area of Triangle B = [tex]A_2[/tex]
So, [tex]A_2[/tex] = [tex]\dfrac{1}{2}[/tex] × b × 2 h ........2
Now, Comparing both equation 1 and 2
∵ [tex]A_2[/tex] = [tex]\dfrac{1}{2}[/tex] × b × 2 h
Or, [tex]A_2[/tex] = 2 × [tex]\dfrac{1}{2}[/tex] × b × h
Or, [tex]A_2[/tex] = 2 × [tex]A_1[/tex]
So, The area of Triangle B = 2 times The area of Triangle A
Hence, The area of Triangle B is twice the area of Triangle A . Answer