The probability of getting a total of 6 is [tex]\frac{5}{36}[/tex]
Fez rolls 2 fair dice and adds the results from each
To find: probability of getting a total of 6
The probability of an event is given as:
[tex]\text { probability of an event }=\frac{\text { number of favorable outcomes }}{\text { total number of possible outcomes }}[/tex]
When we roll 2 fair dice, the possible outcomes are
{(1,1) (1,2)(1,3)(1,4)(1,5) (1,6)
(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6) }
So total number of possible outcomes = 36
Favorable outcome is getting a total of 6
(1, 5), (2, 4), (3, 3), (4, 2), (5, 1)
Thus number of favorable outcomes = 5
Probability of getting a total of 6:
[tex]probability = \frac{5}{36}[/tex]
Thus the probability of getting a total of 6 is [tex]\frac{5}{36}[/tex]
