Answer:
The probability of making at least one of these errors is 0.0025
Step-by-step explanation:
Consider the provided information.
Let P represents the error in processing.
Let F represents the error in filling.
Let R represents the error in retrieving.
The probability of an error in processing is 0.0010: P(P) = 0.0010
The probability of an in filing is 0.0009: P(F) = 0.0009
The probability of an error in retrieving is 0.0012: P(R) = 0.0012,
The probability of an error in processing as well as filing is 0.0002:
P(P∩F) = 0.0002
The probability of an error in processing as well as retrieving is 0.0003,
P(P∩R) = 0.0003
The probability of an error in processing and filing as well as retrieving is 0.0001.
P(P∩F∩R)=0.0001
P(R∩F)=0.0002
The probability of at least one is:
P(P∪F∪R)=P(P)+P(R)+P(F)-P(P∩F)-P(P∩R)-P(R∩F)+P(P∩F∩R)
P(P∪F∪R)=0.0010+0.0009+0.0012-0.0002-0.0002-0.0003+0.0001
P(P∪F∪R)=0.0025
Hence, the probability of making at least one of these errors is 0.0025
The required diagram is shown below.
