A line passes through the points
(P,a) and (P,-a) where p and a are real numbers and p=/0.
Describe each of the following and explain your reasoning please.
1. slope of the line
2. equation of the line
3. Y-intercept
4. slope of a line perpendicular to the given line

Respuesta :

Answer:

Step-by-step explanation:

Slope, m =change in value of y on the vertical axis / change in value of x on the horizontal axis

change in the value of y = y2 - y1

Change in value of x = x2 -x1

y2 = final value of y

y 1 = initial value of y

x2 = final value of x

x1 = initial value of x

From the information given,

y2 = - a

y1 = a

x2 = 0

x1 = 0

Slope = (- a - a)/0-0 = -2a/0 = 0

2) equation of the line is represented in the slope intercept form as y = mx + c

Where

m = slope

c = intercept.

To determine c, we would substitute y = a, x = p and m = 0 into y= mx + c. It becomes

a = 0×p + c

c = a

The equation becomes

y = a

3) y intercept,c = a

4) the slope of a line perpendicular to the given line is a negative reciprocal of the slope of the given line. Therefore,

Slope = - 0 = 0

ACCESS MORE
EDU ACCESS