Question

What is the equation of the line which

includes the points (2, 4) and (14, –2)?


A. y=5x−12

B. y=−12x−5

C. y=−12x+5

D. y=−2x+5

Answer 1

Answer:

The equation of the line is y = (-1/2)x + 5

Step-by-step explanation:

$m = \frac{y2 - y1}{x2 - x1 }$

First of all, have to find gradient using the formula above :

(2,4) & (14,-2)

m = (-2-4) / (14-2)

= -6 / 12

= -1/2

Second, using y = mx + b as b is a constant and is a y-intercept. Using any of these 2 coordinates to find the value of b with given gradient :

y = mx + b

Let y=4 & x=2

4 = (-1/2)(2) + b

b = 4 + 1

= 5

Lastly, put the value of gradient and y-intercept into the equation :

y = mx + b

Let m=-1/2 & b=5

y = (-1/2)x + 5