Question

A concentration cell is constructed by using the same half-reaction for both the cathode and anode. What is the cell potential E at 298K for a concentration cell that combines a silver cathode in contact with 0.10 M silver nitrate and a silver anode in contact with 0.00003 M silver nitrate? (Eored = +0.80 V for Ag/Ag+)

Answer 1

Answer:

$E^o_{cell}=0\ V$

Explanation:

Concentration of silver cathode = $0.10\ M \ AgNO_3.$

Concentration of silver anode = $0.00003\ M \ AgNO_3.$

It is given that , $E^o_{red}=+0.80 \ V.$

We know in a standard cell,

Reduction:

Oxidation : $Ag^++e^-->Ag  \  \  \ \ \ \ \ E^o=+0.80\ V \\ Ag\ ->Ag^++e^-\ \ \ \ \ \  E^o=-0.80\ V$

We know, $E^o_{cell}=E_{red}+ E_{ox}\\=-0.80\ +0.80 \ V\\=0\ V.$

Therefore, $E^o_{cell}=0\ V$

Hence this is the required solution.