The function [tex]f(x)=\left(\frac{1}{5}\right)^{x}[/tex] is decaying.
Step-by-step explanation:
Given:
[tex]f(x)=\left(\frac{1}{5}\right)^{x}[/tex]
The above equation can also write as below,
[tex]f(x)=\frac{1}{5^{x}}[/tex]
Now from the function we can see that as we are increasing the value of x the value of function is decreasing. Let take some values of x and then find out the value of function at those value of x
When x = 1 ,
[tex]f(1)=\frac{1}{5}=0.2[/tex]
When x = 2,
[tex]f(2)=\frac{1}{5^{2}}=\frac{1}{25}=0.04[/tex]
When x = 3,
[tex]f(3)=\frac{1}{5^{3}}=0.008[/tex]
So, from the above examples, we can see that the value of function is decreasing on increasing the value of x. Hence the function is decay