Answer:
23.6 L
Explanation:
Several conversion factors are needed to solve this problem. The following relationships are required:
[tex]1 lb = 453.59 g[/tex]
Now, the density of mercury is:
[tex]d = 13.6 g/mL[/tex]
As well as another conversion factor between liters and milliliters:
[tex]1 L = 1000 mL[/tex]
We might apply dimensional analysis problem solving technique for this problem. We start with lb and we wish to convert into grams first, this is done by multiplying lb by a factor of g/lb, so that pounds cancel out and we obtain grams.
Having grams, we'll multiply by a factor of mL/g to cancel out the grams and obtain milliliters.
After we have milliliters, we'll multiply by L/ml factor to convert into liters finally.
Putting all of this together, we obtain:
[tex]709 lb Hg\cdot \frac{453.59 g}{1 lb}\cdot \frac{1 mL}{13.6 g}\cdot \frac{1 L}{1000 mL} = 23.6 L[/tex]