The linear equation of the initial (red ) incline would be y = __x +__

Answer:
[tex]y=\underline {1.5}x+\underline 0[/tex]
Step-by-step explanation:
From the graph,
The initial red incline is a straight line passing through the origin.
So, a straight line passing through the origin is of the form:
[tex]y=mx+0[/tex]
Where, 'm' is the slope.
Now, the slope of a given as the change in y value to change in x value.
Consider the two end points of the red line (0, 0) and (4, 6).
The slope with two points [tex](x_1,y_1)\ and\ (x_2,y_2)[/tex] on the line is given as:
[tex]m=\frac{(y_2-y_1)}{(x_2-x_1)}[/tex]
Plug in [tex]x_1=0,y_1=0,x_2=4,y_2=6[/tex]. Therefore, slope is:
[tex]m=\frac{6-0}{4-0}\\m=\frac{6}{4}=1.5[/tex]
Hence, the equation of the initial red incline is:
[tex]y=\underline {1.5}x+\underline 0[/tex]