Question

One number is 4 less than 3 times the second number.If t3 more than two times The first number is decreased By two times the second, the result is 11. What are both numbers?

Answer 1

Answer:

4 and 0

Step-by-step explanation:

Let one number be x

Let second number be y

One number = 4-3y

(3+2x)-2y=11

Substitutue one number x in the equation

(3+2(4-3y)) -2y=11

Open inner bracket

(3+8-6y) -2y=11

Open the final bracket

3+8-6y-2y=11

11-8y=11

-8y=11-11

-8y=0

y=0 ( this is because zero cant be divided)

One number = 4-3y

Substitute y

4-3(0)

4-0=4

x=4