Answer:
2x-2
Step-by-step explanation:
Given that there is a function of x as
[tex]f(x)=x^2−2x+5[/tex]
Let us find difference quotient of f
For this, first find f(x+h)
[tex]f(x+h)=(x+h)^2−2(x+h)+5\\=x^2+2xh+h^2-2x-2h+5\\f(x+h)-f(x) = 2xh+h^2-2h\\[/tex]
Divide this by h
[tex]\frac{f(x+h)-f(x)}{h} =2x+h-2\\[/tex]
Take limit as h tends to 0
Difference quotient = 2x-2