Answer:
C₂H₃Cl
Explanation:
We can calculate the compound's molar mass using the data given by the problem and Graham's law:
Rate₁/Rate₂ = [tex]\sqrt{\frac{M_{2}}{M_{1}} }[/tex]
In this case the subscript 1 refers to the compound and 2 refers to Ar.
Keeping in mind that Rate = volume/time, and that the volume is the same for both compounds, we can rewrite the equation as:
Time₂/Time₁ = [tex]\sqrt{\frac{M_{2}}{M_{1}} }[/tex]
6.18/7.73 = [tex]\sqrt{\frac{39.95}{M_{1}} }[/tex]
M₁ = 62.5 g/mol
Now we determine the molecular formula by using the elemental % analysis:
Assuming we have 1 mol of the compound:
C ⇒ 62.5 g * 38.4/100 = 24 g C = 2 mol C
H ⇒ 62.5 g * 4.8/100 = 3 g H = 3 mol H
C ⇒ 62.5 g * 56.8/100 = 35.5 g Cl = 1 mol Cl
Thus the molecular formula is C₂H₃Cl