Question

16. You cross a true breeding pea plant with long, purple seeds to a true breeding pea plant with round, red seeds. All of the F1 progeny have long, purple seeds. When you cross the F1 progeny, you observe the following phenotypic ratios in the F2 generation: Phenotype Count long, purple 40 round, purple 10 long, red 10 round, red 40 What is the genetic distance between the gene control seed shape and the gene controlling seed color?

Answer 1

Answer:

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Explanation:

Answer 2

The genetic distance between the gene control seed shape and the gene controlling seed color is 20 Map units.

A true-breeding cross is a crossing whereby the phenotypic information of the offspring produced is the same as the progenitor.

From the given information:

• When you cross the F1 progeny, you observe the following phenotypic ratios in the F2 generation:

Phenotype       Count

Long, Purple      40

Round, Purple    10

Long, Red           10

Round, Red         40

The genetic distance between genes is determined by calculating the percentage of recombination.

Recall that:

• Recombination is the production of new alleles at two or even more loci

The percentage of recombination is the division of the overall total number of recombinants with the total number of progeny multiplied by a hundred percent.

Mathematically;

$\mathbf{percentage \ of \ recombination = \dfrac{total \ no \ of \ recombination}{amount \ of \ progeny} \times 100}$

• Since the frequency of recombinant gene are usually low;

The recombinant genes are:

• round purple and long red phenotypes.

$\mathbf{percentage \ of \ recombination = \dfrac{10 + 10}{40+10+10+40} \times 100}$

$\mathbf{percentage \ of \ recombination = \dfrac{20}{100} \times 100}$

percentage of recombination = 20 Map Units

Therefore, we can conclude that the percentage of recombination which indicates the genetic distance is 20 Map Units

Learn more about genetic distance here:

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