Question

A ball of mass 24 g is attached to a cord of length 0.463 m and rotates in a vertical circle. What is the minimum speed the ball must have at the top of the circle so the cord does not become slack? The acceleration of gravity is 9.8 m/s 2 . Answer in units of m/s.

Answer 1

Answer:2.13 m/s

Explanation:

Given

mass of ball $m=24 gm$

Length of cord $L=0.463 m$

acceleration due to gravity $g=9.8 m/s^2$

minimum velocity after which cord will slack

$\frac{mv^2}{r}=mg$

$v=\sqrt{rg}$

$v=\sqrt{0.463\times 9.8}$

$v=2.13 m/s$