Question

A horse draws a sled horizontally across a snow-covered field. The coefficient of friction between the sled and the snow is 0.135, and the mass of the sled, including the load, is 195.9kg. If the horse moves the sled at a constant speed of 1.785m/s, what is the power needed to accomplish this?

Answer 1

Answer:

P = 462.62 watts

Explanation:

The power needed to accomplish this can be calculated how

P = Fv

    Where F:  The force exerted by the horse

                v:  velocity

The force exerted by the horse is against friction force; how the movement is with constant velocity these forces must be equals, then

Fr = μN

    =μmg

    = (0.135)(195.9)(9.8)

    = 259.17 N

And the power is

P = (259.17)(1.785)

P = 462.62 watts

Answer 2

The power needed to accomplish this is 462.62 watts.

What is the coefficient of friction?

It is defined as the numerical value that indicates the amount of friction present between the surfaces of two bodies. The lower the coefficient of friction the lower the friction between the surfaces and the higher coefficient of friction the higher the friction force between them.

We know the:

P = F×v

Where P is the power needed to accomplish this.

F = force exerted by the horse

v = velocity of the horse.

For F = $\rm \mu N$

$\mu = 0.135$

N = mg ⇒ 195.9×9.8   ( m= 195.9 kg and g = 9.8 $\rm m/sec^2$)

N = 1919.82 Newtons

F = 0.135×1919.82 ⇒ 259.1757 Newtons

Now P = F×v ⇒259.1757×1.785

P = 462.62  Watts

Thus, the power needed to accomplish this is 462.62 watts.

Learn more about the coefficient of friction here:

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