Answer:
The slope of AB is [tex]\frac{4}{3}[/tex], the slope of BC is [tex]- \frac{2}{7}[/tex], the slope of CD is [tex]\frac{4}{3}[/tex], and the slope of AD is [tex]- \frac{2}{7}[/tex], Quadrilateral ABCD is a parallelogram because both pair of opposite sides are parallel.
Step-by-step explanation:
The quadrilateral ABCD has vertices A(-5,1), B(-2,5), C(5,3) and D(2,-1).
Now, slope of line AB = [tex]\frac{5 - 1}{- 2 - ( - 5)} = \frac{4}{3}[/tex]
Slope of line BC = [tex]\frac{3 - 5}{5 - (- 2)} = - \frac{2}{7}[/tex]
Slope of line CD = [tex]\frac{- 1 - 3}{2 - 5} = \frac{4}{3}[/tex]
And slope of DA = [tex]\frac{1 - ( - 1)}{- 5 - 2} = -\frac{2}{7}[/tex]
Therefore, the slope of AB is [tex]\frac{4}{3}[/tex], the slope of BC is [tex]- \frac{2}{7}[/tex], the slope of CD is [tex]\frac{4}{3}[/tex], and the slope of AD is [tex]- \frac{2}{7}[/tex], Quadrilateral ABCD is a parallelogram because both pair of opposite sides are parallel. (Answer)