Respuesta :

r3t40

We have:

[tex]

\begin{cases}

y=2x+9 \\

y=-x+6 \\

\end{cases}

[/tex]

First multiply the second equation by 2 to get:

[tex]

\begin{cases}

y=2x+9 \\

2y=-2x+12 \\

\end{cases}

[/tex]

Then add the equations to eliminate the x-terms to get:

[tex]3y=21\Longrightarrow y=7[/tex]

And finally use calculated y and plug it in one of the original equations to find x:

[tex]7=6-x\Longrightarrow x=-1[/tex]

The solution is a point [tex]P(-1,7)[/tex] where lines [tex]y=2x+9[/tex] and [tex]y=6-x[/tex] intersect.

Hope this helps.

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