Aqueous solutions of sodium sulfide and copper(II) chloride are mixed together. Which statement is correct?

A. CuS will precipitate from solution.
B. No reaction will occur.
C. NaCl will precipitate from solution.
D. A gas is released.
E. Both NaCl and CuS precipitate from solution.

Respuesta :

Answer:

Correct statement is A.

Explanation:

Let's see the reactions:

2Na⁺  +  S⁻²  → Na₂S (aq)

This salt is soluble

CuCl₂  (aq)  →  Cu²⁺  +  2Cl⁻

This is an insoluble salt.

Cu²⁺ (aq) +  2Cl⁻ (aq) +  2Na⁺ (aq)  +  S⁻² (aq)  →   2NaCl (aq)  +  CuS (s) ↓

No molecules or gas are formed. (Option D, FALSE)

NaCl does not precipitate, because it'a soluble salt (OPTION E or C are false)

Option B is also false. There is a reaction, of precipitation.

Answer:

A.

Explanation:

Firstly, let’s write a chemical equation for the observation:

Na2S + CuCl2 → CuS + 2NaCl

It should be noted that the copper sulphide is a solid and the sodium chloride is in the aqueous form.

B. Is incorrect. A chemical reaction will occur. The chemical reaction will yield copper sulphide and aqueous sodium chloride.

C. is incorrect. Sodium chloride is in the solution form and cannot precipitate in that form.

D. Is incorrect as no gas is released

E. Is incorrect, only copper sulphide will precipitate.

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