Answer: Second option.
Step-by-step explanation:
By defintion, a Quadratic function is a polynomial of degree 2 and it has the following form:
[tex]f(x)=ax^2+bx+c[/tex]
Therefore, the function given is Quadratic. This is:
[tex]f(x)=x^2 + 6x +9[/tex]
The steps to find the roots (or the x-intercepts) of the function, are:
1. You must substitute [tex]f(x)=0[/tex]:
[tex]0=x^2 + 6x +9[/tex]
2. Now, you can factor the Quadratic equation. Choose two numbers whose sum is 6 and whose product is 9. Notice that:
[tex]3+3=6\\3*3=9[/tex]
Therefore, you will get a "Double root".
4. So the solution is:
[tex](x+3)^2=0\\\\x=-3[/tex]
