Question

If an object is thrown downward with an initial velocity of v 0​, then the distance it travels is given by sequals4.9tsquaredplusv 0t. An object is thrown downward from a cliff 400 m high and it travels 138.3 m in 3 sec. What was the initial velocity of the​ object?

Answer 1

Initial velocity of the​ object = 31.4 m/s

Explanation:

If an object is thrown downward with an initial velocity of v₀​, then the distance it travels is given by s = 4.9 t²+v₀t

Now an object is thrown downward from a cliff 400 m high and it travels 138.3 m in 3 sec. We need to find initial velocity of the​ object.

           s = 4.9 t²+v₀t

           138.3 = 4.9  x 3²+ v₀ x 3

             3v₀ = 94.2

               v₀ = 31.4 m/s

Initial velocity of the​ object = 31.4 m/s