Respuesta :
Answer:
The quantity after t years 40 [tex](0.65)^{\textrm t}[/tex] millions tons
Step-by-step explanation:
Given as :
The rate of decrease of carbon dioxide each other = 35%
The quantity of carbon dioxide emitted this year = 40 million tons
Let the quantity of carbon dioxide emitted after t year = A millions tons
Now, According to question
The quantity of carbon dioxide emitted after t year = The quantity of carbon dioxide emitted this year × [tex](1-\dfrac{\textrm rate}{100})^{\textrm time}[/tex]
Or, A millions tons = 40 millions tons × [tex](1-\dfrac{\textrm 35}{100})^{\textrm t}[/tex]
Or, A millions tons = 40 millions tons × [tex](\dfrac{100-35}{100})^{\textrm t}[/tex]
Or, A millions tons = 40 millions tons × [tex](\dfrac{65}{100})^{\textrm t}[/tex]
Or, A millions tons = 40 millions tons × [tex](0.65)^{\textrm t}[/tex]
So,The quantity after t years = A = 40 [tex](0.65)^{\textrm t}[/tex] millions tons
Hence The quantity after t years 40 [tex](0.65)^{\textrm t}[/tex] millions tons Answer