Answer:
The molarity of the solution is 1.854 mol/L
Explanation:
The weight of [tex]Na_{2}C_{2}O_{4}[/tex] present in 131.64mL of 2.7 M solution:
[tex]Molarity=\frac{no.\:of\:moles}{Volume\:of\:solution\:in\:L}\\Molarity\:of\:the\:solution=2.7M\\Volume\:of\:solution=131.64ml=0.13164L\\No.\:of\:moles=0.355428\\Weight\:of\:Na_{2}C_{2}O_{4}=43.36g\\To\:this\:solution\:14.13g\:of\:Na_{2}C_{2}O_{4}\:is\:added.\\Total\:weight\:of\:Na_{2}C_{2}O_{4}=57.49g\\No.\:of\:moles=0.471\\Final\:Volume\:of\:Solution=254.18mL=0.25418L\\Molarity\:of\:the\:final\:solution=\frac{0.471}{0.25418}=1.854\:mol/L[/tex]
Hence, the molarity of the solution is 1.854 mol/L
