Question

As a 70-kg person stands at the seashore gazing at the tides (which are caused by the Moon),
how large is the gravitational force on that person due to the Moon? The mass of the Moon is
7.35 x 1022 kg, the distance to the Moon is 3.82 * 108 m, and G = 6.67 x 10-11 Nm2/kg2.

Answer 1

Answer:

The force on that person due to the moon is F=0.00235[N]

Explanation:

We can solve this problem using universal gravitational law.

Data:

m1 = mass of the person, 70 [kg]

m2 = mass of the moon, 7.35*10^22 [kg]

G = universal constant of gravity, 6.67*10^-11 [ N*m^2/(kg^2)]

r = diatance from moon to the earth, 3.82*10^8[m]

$F=G*\frac{m_{1}*m_{2}  }{r^{2} } \\replacing the values we have\\F=6.67*10^-11*\frac{70*7.35*10^{22} }{ (3.82*10^{8})^{2}  } \\F=0.00235[N]$