Answer: [tex]S_{29}[/tex] = 2001
Step-by-step explanation:
Since the sequence is an arithmetic sequence , it means that a common difference must exist.
Let the terms in the sequence be [tex]T_{1}[/tex] , [tex]T_{2}[/tex] , [tex]T_{3}[/tex] , [tex]T_{4}[/tex] , ...
Then common difference = [tex]T_{2}[/tex] - [tex]T_{1}[/tex] = [tex]T_{3}[/tex] - [tex]T_{2}[/tex] = 8
That is , the common difference (d) = 8
The formula for calculating sum of n terms is given by :
[tex]S_{n}[/tex] = [tex]\frac{n}{2}[/tex] [ 2a + (n-1)d ]
Where ;
n = number of terms
a = first term
d = common difference
From the question :
n = 29
a = -43
d = 8
Substituting into the formula , we have
[tex]S_{29}[/tex] = [tex]\frac{29}{2}[/tex] [ 2{-43} + (29-1)(8) ]
[tex]S_{29}[/tex] = [tex]\frac{29}{2}[/tex] (-86 +224)
[tex]S_{29}[/tex] = [tex]\frac{29}{2}[/tex] ( 138)
[tex]S_{29}[/tex] = [tex]\frac{4002}{2}[/tex]
[tex]S_{29}[/tex] = 2001