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What is the sum of the first 29 terms of the arithmetic sequence? −43,−35,−27,−19,... Enter your answer in the box. S29=

Respuesta :

Answer: [tex]S_{29}[/tex] = 2001

Step-by-step explanation:

Since the sequence is an arithmetic sequence , it means that a common difference must exist.

Let the terms in the sequence be [tex]T_{1}[/tex] , [tex]T_{2}[/tex] , [tex]T_{3}[/tex] , [tex]T_{4}[/tex] , ...

Then common difference = [tex]T_{2}[/tex] - [tex]T_{1}[/tex] = [tex]T_{3}[/tex] - [tex]T_{2}[/tex] = 8

That is , the common difference (d) = 8

The formula for calculating sum of  n terms is given by :

[tex]S_{n}[/tex] = [tex]\frac{n}{2}[/tex] [ 2a + (n-1)d ]

Where ;

n = number of terms

a = first term

d = common difference

From the question :

n = 29

a = -43

d = 8

Substituting into the formula , we have

[tex]S_{29}[/tex] = [tex]\frac{29}{2}[/tex] [ 2{-43} + (29-1)(8) ]

[tex]S_{29}[/tex] = [tex]\frac{29}{2}[/tex] (-86 +224)

[tex]S_{29}[/tex] = [tex]\frac{29}{2}[/tex] ( 138)

[tex]S_{29}[/tex] = [tex]\frac{4002}{2}[/tex]

[tex]S_{29}[/tex] = 2001

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