Question

An ice-making machine inside a refrigerator operates in a Carnot cycle. It takes heat from liquid water at 0.0 ∘C and rejects heat to a room at a temperature of 20.3 ∘C. Suppose that liquid water with a mass of 82.0 kg at 0.0 ∘C is converted to ice at the same temperature. Take the heat of fusion for water to be Lf = 3.34×105 J/kg .

Answer 1

Answer:

Energy required = $J=2.73\times10^7 \ J.$

Explanation:

We know according to zeroth law of Thermodynamics, all bodies in a close system remains in thermal equilibrium.

Means, Energy gain by one part of system = energy loss by one another part of system.

Here, energy is given to surrounding and it is lost by water.

Therefore, its temperature decreases.

Energy required to convert 82 kg liquid, E = $m\times L$.

Here, $m=82 \ kg$

         $L=larent \ heat \ of \ fusion=3.34\times 10^5J/kg.$.

E=$82 \times 3.34\times 10^5\ J=2.73\times10^7 \ J.$