Question

HELP ASAP 30 POINTS! GIVING BRAINLIEST TO THE CORRECT ANSWER

Which equation has the same solution as this equation?

x^2-16x+12=0

A) (x-8)^2 = 144

B) (x-4)^2 =4

C) (x-8)^2 = 52

D) (x-4)^2 = 16

Answer 1

Answer:

Option C. $(x-8)^{2}=52$

Step-by-step explanation:

we have

$x^{2}-16x+12=0$

Complete the square

$(x^{2}-16x+8^2)+12-8^2=0$

$(x^{2}-16x+64)+12-64=0$

$(x^{2}-16x+64)-52=0$

rewrite as perfect squares

$(x-8)^{2}-52=0$

Move the constant to the right side

$(x-8)^{2}=52$