Question

A line passes through the points (–5, 2) and (10, –1). Which is the equation of the line? 025-1. c025-2 y = –5x – 23 y = 5x + 27

Answer 1

Answer:

y=-1/5x+1

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-1-2)/(10-(-5))

m=-3/(10+5)

m=-3/15

m=-1/5

y-y1=m(x-x1)

y-2=-1/5(x-(-5))

y-2=-1/5(x+5)

y=-1/5x-5/5+2

y=-1/5x-1+2

y=-1/5x+1