contestada

the T 1/2 of a certain radioisotope is 4 weeks what fraction of the original isotope remains after 12 weeks​

Respuesta :

Answer:

The fraction of original isotope remaining after 12 weeks is 1/8 (0.125)

Explanation:

The half life of the radio-isotope = 4 weeks =[tex]t_{\frac{1}{2}}[/tex]

After n half lives, the fraction of original isotope remaining = [tex]\frac{1}{2^{n}}[/tex]

In 12 weeks, the number of half lives = 12/4 = 3 half lives

The fraction of original isotope remaining = [tex]\frac{1}{2^{3}}=\frac{1}{8}[/tex]

Hence, after 12 weeks, fraction of original isotope remaining is 1/8 (0.125)

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