Answer:
The output is 1.
Explanation:
int x = 1;
do{
System.out.print(x + " ");
x--;
}while (x > 0);
System.out.println();
The statement above is an example of a do-while loop which is always executed at least once.
In the above code snippet:
1 is assigned to x in the first line. Then the do keyword start the loop block. Inside the loop block, the value of x is output which is one (1). Then, the value of x is decreased by one, making x = 0. Then, the while keyword is reached where the condition is tested. The condition check whether x > 0 i.e whether 0 > 0. Off course, the condition is false and the loop is exited.
The last statement print a single line to the screen.
