Explanation:
Refer the given figure,
BC = Length of string = 39 feet
∠B = 65°
We need to find height of the kite , that is AC = h
We have
[tex]sinB=\frac{AC}{BC}\\\\sin65=\frac{h}{39}\\\\h=39\times sin65\\\\h=35.35ft[/tex]
The kite is at a height 35.35 feet.