Rectangle A is a scaled version of rectangle B. The dimensions of rectangle A are three times the dimensions of rectangle B. The area of rectangle B is 162 sq cm. What is the area of rectangle A?

because each dimension of A is 3 tomes each dimension of B, that will mean that both the length and width of B are multiplied by 3 in order to get the length and width of A, so the area of B is length×width=162 and the area of A (in terms of B's dimensions) is 3xlength×3×width=9×length×width=9×162=1458 sq cm

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rohiraakshay4 rohiraakshay4 · Answer 2 · 2022-05-27T05:56:08+02:00

The required area of the rectangle A is 1458 sq. cm which is 9 times the area of the rectangle B

Area of Rectangle:

The area of the rectangle can be calculated as the product of length a and width b is

Area = a b

How to calculate area of the rectangle ?

Here we have given that

The dimension of rectangle A = 3 times the dimension of rectangle B

Let the length of the rectangle B is a and width of the rectangle is b then

The length of rectangle A = 3a

The width of rectangle A = 3b

Also we have given

Area of the rectangle B = 162 sq. cm

a b = 162 sq. cm

Now the area of the rectangle A = 3a x 3b = 9 ab

Using the value of ab = 162 sq. cm

Area of the rectangle A = 9 x 162 = 1458 sq. cm

This is the conclusion to the answer.

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