Given the triangle below, what is m < B, rounded to the nearest tenth

Answer:
Therefore m∠ B is 42.1°
Step-by-step explanation:
Given:
In Δ ABC
AB = 15 = c
AC = 18 = b
∠ C = 34°
To Find:
∠ B = ?
Solution:
In Δ ABC We have Sine Rule as
[tex]\frac{a}{\sin A}= \frac{b}{\sin B}= \frac{c}{\sin C}[/tex]
Substituting the given values we get
[tex]\frac{b}{\sin B}= \frac{c}{\sin C}[/tex]
[tex]\frac{18}{\sin B}= \frac{15}{\sin 34}\\\\\sin B=0.671\\\\\therefore B=\sin^{-1}(0.671)=42.14\°[/tex]
Therefore m∠ B is 42.1°