Question

What is the result of subtracting the second equation from the first?
−3x+2y=7−3x−2y=4\begin{aligned} -3x+2y &= 7 \\\\ -3x-2y &= 4 \end{aligned}
−3x+2y

−3x−2y
​

=7
=4
​

Answer 1

Answer:

The values of x and y from the given equations are $x= -\frac{\bf 11}{\bf 6}$ and  $y=\frac{\bf 3}{\bf 4}$

Step-by-step explanation:

Given equations are

$-3x+2y=7\hfill (1)$   and  $-3x-2y=4\hfill (2)$

Now subtracting the Equation (2) from the equation (1) we get

$-3x+2y=7$

$3x+2y=-4$        (signs can be changed so x getting        cancelled)

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          4y=3

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we get $4y=3$

Therefore $y=\frac{3}{4}$

Now substituting y value in equation (1)

$-3x+2y=7$

$-3x+2\times \frac{3}{4}=7$

$-3x+ \frac{3}{2}=7$

$-3x=7 - \frac{3}{2}$

$-3x= \frac{14-3}{2}$

$-3x= \frac{11}{2}$

$x= -\frac{11}{6}$

Therefore  $x= -\frac{11}{6}$  and  $y=\frac{3}{4}$