b. Jerome plays middle linebacker for South's varsity football team. In a game against
cross-town rival North, he delivered a hit to North's 82-kg running back, changing his
eastward velocity of 5.6 m/s into a westward velocity of 2.5 m/s. Determine the
impulse delivered to the running back.
a. 210 kgm/s
b. 250 kgm/s
C. 460 kgm/s
d. 670 kgm/s

Respuesta :

Answer:

Option D

670 Kg.m/s

Explanation:

Initial momentum is given by mv=82*5.6=459.2 Kg.m/s (taking eastward as positive)

Final momentum is also mv but v being westward direction, we take it negative

Final momentum=82*-2.5= -205 Kg.m/s

Change in momentum=Final momentum-Initial momentum=-205-459.2=-664.2 Kg.m/s

Impulse=change in momentum=664.2 Kg.m/s rounded off as 670 Kg.m/s

The impulse delivered to the running back is d. 670 kgm/s.

Calculation of impulse:

Since Initial momentum is provided by

=  mv

=82*5.6

=459.2 Kg.m

Now

Final momentum should be

= 82* -2.5

= -205 Kg.m/s

Now

Change in momentum should be

= Final momentum - Initial momentum

= -205-459.2

= -664.2 Kg.m/s

Now finally

Impulse=change in momentum=664.2 Kg.m/s = 670 Kg.m/s

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