Question

A parabola that has a vertex of (3, -2) , a focus of ( 3, -2 1/16) , and opens downward. Which of the following best represents the equation of the parabola in standard form?

Answer 1

Answer:

$y=-x^{2} +6x-11$

Step-by-step explanation:

Given:

Parabola opens downward:

The general equation for a parabola opening downward with vertex at (a,b):

$y-b=-(x-a)^{2}$

In this case vertex is (3,-2) , hence the equation is:

$y-(-2)=-(x-3)^2$

$y+2=-x^{2} +6x-9$

$y=-x^{2} +6x-11$

Answer 2

Answer:

y = –x2 + 6x – 11

Step-by-step explanation:

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